Skip to content

128. Longest Consecutive Sequence 👍

  • Time: $O(n)$
  • Space: $O(n)$
 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
class Solution {
 public:
  int longestConsecutive(vector<int>& nums) {
    int ans = 0;
    unordered_set<int> seen{begin(nums), end(nums)};

    for (int num : nums) {
      // num is the start of a sequence
      if (seen.count(num - 1))
        continue;
      int length = 1;
      while (seen.count(++num))
        ++length;
      ans = max(ans, length);
    }

    return ans;
  }
};
 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
class Solution {
  public int longestConsecutive(int[] nums) {
    int ans = 0;
    Set<Integer> seen = Arrays.stream(nums).boxed().collect(Collectors.toSet());

    for (int num : nums) {
      // num is the start of a sequence
      if (seen.contains(num - 1))
        continue;
      int length = 1;
      while (seen.contains(++num))
        ++length;
      ans = Math.max(ans, length);
    }

    return ans;
  }
}
 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
class Solution:
  def longestConsecutive(self, nums: List[int]) -> int:
    ans = 0
    seen = set(nums)

    for num in nums:
      if num - 1 in seen:
        continue
      length = 0
      while num in seen:
        num += 1
        length += 1
      ans = max(ans, length)

    return ans
Back to top