# 892. Surface Area of 3D Shapes

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  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 class Solution { public: int surfaceArea(vector>& grid) { int ans = 0; for (int i = 0; i < grid.size(); ++i) for (int j = 0; j < grid.size(); ++j) { if (grid[i][j]) ans += grid[i][j] * 4 + 2; if (i) ans -= min(grid[i][j], grid[i - 1][j]) * 2; if (j) ans -= min(grid[i][j], grid[i][j - 1]) * 2; } return ans; } }; 
  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 class Solution { public int surfaceArea(int[][] grid) { int ans = 0; for (int i = 0; i < grid.length; ++i) for (int j = 0; j < grid.length; ++j) { if (grid[i][j] > 0) ans += grid[i][j] * 4 + 2; if (i > 0) ans -= Math.min(grid[i][j], grid[i - 1][j]) * 2; if (j > 0) ans -= Math.min(grid[i][j], grid[i][j - 1]) * 2; } return ans; } } 
  1 2 3 4 5 6 7 8 9 10 11 12 13 14 class Solution: def surfaceArea(self, grid: List[List[int]]) -> int: ans = 0 for i in range(len(grid)): for j in range(len(grid)): if grid[i][j]: ans += grid[i][j] * 4 + 2 if i: ans -= min(grid[i][j], grid[i - 1][j]) * 2 if j: ans -= min(grid[i][j], grid[i][j - 1]) * 2 return ans