1266. Minimum Time Visiting All Points ¶ Time: Space: C++JavaPython 1 2 3 4 5 6 7 8 9 10 11 12class Solution { public: int minTimeToVisitAllPoints(vector<vector<int>>& points) { int ans = 0; for (int i = 1; i < points.size(); ++i) ans += max(abs(points[i][0] - points[i - 1][0]), abs(points[i][1] - points[i - 1][1])); return ans; } }; 1 2 3 4 5 6 7 8 9 10 11class Solution { public int minTimeToVisitAllPoints(int[][] points) { int ans = 0; for (int i = 1; i < points.length; ++i) ans += Math.max(Math.abs(points[i][0] - points[i - 1][0]), Math.abs(points[i][1] - points[i - 1][1])); return ans; } } 1 2 3 4 5 6 7 8 9class Solution: def minTimeToVisitAllPoints(self, points: list[list[int]]) -> int: ans = 0 for i in range(1, len(points)): ans += max(abs(points[i][0] - points[i - 1][0]), abs(points[i][1] - points[i - 1][1])) return ans