1437. Check If All 1's Are at Least Length K Places Away¶ Time: Space: Python 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17class Solution: def kLengthApart(self, nums: list[int], k: int) -> bool: if k == 0: return True n = len(nums) curr = 0 next = 1 while curr < n and next < n: if nums[next] == 1: if nums[curr] == 1 and next - curr <= k: return False curr = next next += 1 return True