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1442. Count Triplets That Can Form Two Arrays of Equal XOR 👍

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class Solution:
  def countTriplets(self, arr: list[int]) -> int:
    ans = 0
    xors = [0]
    prefix = 0

    for i, a in enumerate(arr):
      prefix ^= a
      xors.append(prefix)

    for j in range(1, len(arr)):
      for i in range(0, j):
        xors_i = xors[j] ^ xors[i]
        for k in range(j, len(arr)):
          xors_k = xors[k + 1] ^ xors[j]
          if xors_i == xors_k:
            ans += 1

    return ans