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1582. Special Positions in a Binary Matrix 👍

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class Solution {
 public:
  int numSpecial(vector<vector<int>>& mat) {
    const int m = mat.size();
    const int n = mat[0].size();
    int ans = 0;
    vector<int> rowOnes(m);
    vector<int> colOnes(n);

    for (int i = 0; i < m; ++i)
      for (int j = 0; j < n; ++j)
        if (mat[i][j] == 1) {
          ++rowOnes[i];
          ++colOnes[j];
        }

    for (int i = 0; i < m; ++i)
      for (int j = 0; j < n; ++j)
        if (mat[i][j] == 1 && rowOnes[i] == 1 && colOnes[j] == 1)
          ++ans;

    return ans;
  }
};

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class Solution {
  public int numSpecial(int[][] mat) {
    final int m = mat.length;
    final int n = mat[0].length;
    int ans = 0;
    int[] rowOnes = new int[m];
    int[] colOnes = new int[n];

    for (int i = 0; i < m; ++i)
      for (int j = 0; j < n; ++j)
        if (mat[i][j] == 1) {
          ++rowOnes[i];
          ++colOnes[j];
        }

    for (int i = 0; i < m; ++i)
      for (int j = 0; j < n; ++j)
        if (mat[i][j] == 1 && rowOnes[i] == 1 && colOnes[j] == 1)
          ++ans;

    return ans;
  }
}

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class Solution:
  def numSpecial(self, mat: List[List[int]]) -> int:
    m = len(mat)
    n = len(mat[0])
    ans = 0
    rowOnes = [0] * m
    colOnes = [0] * n

    for i in range(m):
      for j in range(n):
        if mat[i][j] == 1:
          rowOnes[i] += 1
          colOnes[j] += 1

    for i in range(m):
      for j in range(n):
        if mat[i][j] == 1 and rowOnes[i] == 1 and colOnes[j] == 1:
          ans += 1

    return ans