Array Sorting 1619. Mean of Array After Removing Some Elements¶ Time: C++: $O(n)$, Java/Python: $O(\texttt{sort})$ Space: C++: $O(1)$, Java/Python: $O(\texttt{sort})$ C++JavaPython 1 2 3 4 5 6 7 8 9 10class Solution { public: double trimMean(vector<int>& arr) { int offset = arr.size() / 20; nth_element(arr.begin(), arr.begin() + offset, arr.end()); nth_element(arr.begin() + offset, arr.end() - offset, arr.end()); double sum = accumulate(arr.begin() + offset, arr.end() - offset, 0.0); return sum / (arr.size() - offset * 2); } }; 1 2 3 4 5 6 7class Solution { public double trimMean(int[] arr) { Arrays.sort(arr); final int offset = arr.length / 20; return Arrays.stream(Arrays.copyOfRange(arr, offset, arr.length - offset)).average().orElse(0); } } 1 2 3 4 5class Solution: def trimMean(self, arr: list[int]) -> float: arr.sort() offset = len(arr) // 20 return mean(arr[offset:-offset]) Was this page helpful? Thanks for your feedback! Thanks for your feedback! Help us improve this page by using our feedback form.