Database 1633. Percentage of Users Attended a Contest ¶ SQL 1 2 3 4 5 6 7 8 9 10 11 12SELECT contest_id, ROUND( COUNT(user_id) * 100 / ( SELECT COUNT(*) FROM Users ), 2 ) AS percentage FROM Register GROUP BY 1 ORDER BY percentage DESC, contest_id; Was this page helpful? Thanks for your feedback! Thanks for your feedback! Help us improve this page by using our feedback form.