1832. Check if the Sentence Is Pangram ¶ Time: $O(n)$ Space: $O(26) = O(1)$ C++JavaPython 1 2 3 4 5 6class Solution { public: bool checkIfPangram(string sentence) { return unordered_set(sentence.begin(), sentence.end()).size() == 26; } }; 1 2 3 4 5 6 7 8 9 10class Solution { public boolean checkIfPangram(String sentence) { Set<Character> seen = new HashSet<>(); for (final char c : sentence.toCharArray()) seen.add(c); return seen.size() == 26; } } 1 2 3class Solution: def checkIfPangram(self, sentence: str) -> bool: return len(set(sentence)) == 26