1929. Concatenation of Array ¶ Time: $O(n)$ Space: $O(n)$ C++JavaPython 1 2 3 4 5 6 7 8 9 10 11class Solution { public: vector<int> getConcatenation(vector<int>& nums) { const int n = nums.size(); for (int i = 0; i < n; ++i) nums.push_back(nums[i]); return nums; } }; 1 2 3 4 5 6 7 8 9 10 11 12class Solution { public int[] getConcatenation(int[] nums) { final int n = nums.length; int[] ans = new int[n * 2]; for (int i = 0; i < n; ++i) ans[i] = ans[i + n] = nums[i]; return ans; } } 1 2 3class Solution: def getConcatenation(self, nums: list[int]) -> list[int]: return nums * 2