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1985. Find the Kth Largest Integer in the Array 👍

  • Time: $O(n\log k)$
  • Space: $O(k)$
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class Solution {
 public:
  // Similar to 215. Kth Largest Element in an Array
  string kthLargestNumber(vector<string>& nums, int k) {
    auto compare = [](const string& a, const string& b) {
      return a.length() == b.length() ? a > b : a.length() > b.length();
    };
    priority_queue<string, vector<string>, decltype(compare)> minHeap(compare);

    for (const string& num : nums) {
      minHeap.push(num);
      if (minHeap.size() > k)
        minHeap.pop();
    }

    return minHeap.top();
  }
};

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class Solution {
  // Similar to 215. Kth Largest Element in an Array
  public String kthLargestNumber(String[] nums, int k) {
    Queue<String> minHeap = new PriorityQueue<>(
        Comparator.comparingInt(String::length).thenComparing(String::compareTo));

    for (final String num : nums) {
      minHeap.offer(num);
      if (minHeap.size() > k)
        minHeap.poll();
    }

    return minHeap.poll();
  }
}

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class Solution:
  # Similar to 215. Kth Largest Element in an Array
  def kthLargestNumber(self, nums: list[str], k: int) -> str:
    minHeap = []

    for num in nums:
      heapq.heappush(minHeap, int(num))
      if len(minHeap) > k:
        heapq.heappop(minHeap)

    return str(minHeap[0])