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2011. Final Value of Variable After Performing Operations 👍

  • Time: $O(n)$
  • Space: $O(1)$
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class Solution {
 public:
  int finalValueAfterOperations(vector<string>& operations) {
    int ans = 0;

    for (const string& op : operations)
      ans += op[1] == '+' ? 1 : -1;

    return ans;
  }
};

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class Solution {
  public int finalValueAfterOperations(String[] operations) {
    int ans = 0;

    for (final String op : operations)
      ans += op.charAt(1) == '+' ? 1 : -1;

    return ans;
  }
}

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class Solution:
  def finalValueAfterOperations(self, operations: list[str]) -> int:
    return sum(op[1] == '+' or -1 for op in operations)