2022. Convert 1D Array Into 2D Array ¶ Time: $O(mn)$ Space: $O(mn)$ C++JavaPython 1 2 3 4 5 6 7 8 9 10 11 12 13 14class Solution { public: vector<vector<int>> construct2DArray(vector<int>& original, int m, int n) { if (original.size() != m * n) return {}; vector<vector<int>> ans(m, vector<int>(n)); for (int i = 0; i < original.size(); ++i) ans[i / n][i % n] = original[i]; return ans; } }; 1 2 3 4 5 6 7 8 9 10 11 12 13class Solution { public int[][] construct2DArray(int[] original, int m, int n) { if (original.length != m * n) return new int[][] {}; int[][] ans = new int[m][n]; for (int i = 0; i < original.length; ++i) ans[i / n][i % n] = original[i]; return ans; } } 1 2 3 4 5 6 7 8 9 10 11class Solution: def construct2DArray(self, original: List[int], m: int, n: int) -> List[List[int]]: if len(original) != m * n: return [] ans = [[0] * n for _ in range(m)] for i, num in enumerate(original): ans[i // n][i % n] = num return ans