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2185. Counting Words With a Given Prefix 👍

  • Time: $O(n)$
  • Space: $O(1)$
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class Solution {
 public:
  int prefixCount(vector<string>& words, string pref) {
    return ranges::count_if(
        words, [&](const string& word) { return word.find(pref) == 0; });
  }
};

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class Solution {
  public int prefixCount(String[] words, String pref) {
    return (int) Arrays.stream(words).filter(w -> w.startsWith(pref)).count();
  }
}

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class Solution:
  def prefixCount(self, words: list[str], pref: str) -> int:
    return sum(word.startswith(pref) for word in words)