223. Rectangle Area¶ Time: $O(1)$ Space: $O(1)$ C++JavaPython 1 2 3 4 5 6 7 8 9class Solution { public: int computeArea(long A, long B, long C, long D, // long E, long F, long G, long H) { const long x = max(A, E) < min(C, G) ? (min(C, G) - max(A, E)) : 0; const long y = max(B, F) < min(D, H) ? (min(D, H) - max(B, F)) : 0; return (C - A) * (D - B) + (G - E) * (H - F) - x * y; } }; 1 2 3 4 5 6 7class Solution { public int computeArea(long A, long B, long C, long D, long E, long F, long G, long H) { final long x = Math.max(A, E) < Math.min(C, G) ? (Math.min(C, G) - Math.max(A, E)) : 0; final long y = Math.max(B, F) < Math.min(D, H) ? (Math.min(D, H) - Math.max(B, F)) : 0; return (int) ((C - A) * (D - B) + (G - E) * (H - F) - x * y); } } 1 2 3 4 5 6 7class Solution: def computeArea(self, A: int, B: int, C: int, D: int, E: int, F: int, G: int, H: int) -> int: x = min(C, G) - max(A, E) if max(A, E) < min(C, G) else 0 y = min(D, H) - max(B, F) if max(B, F) < min(D, H) else 0 return (C - A) * (D - B) + (G - E) * (H - F) - x * y