class Solution {
public:
long long countGood(vector<int>& nums, int k) {
long ans = 0;
int pairs = 0;
unordered_map<int, int> count;
for (int l = 0, r = 0; r < nums.size(); ++r) {
// Since there're count[r] nums[r]s, including nums[r] to the window will
// increase the number of good subarrays by count[r].
pairs += count[nums[r]]++;
while (pairs >= k)
pairs -= --count[nums[l++]];
// nums[0..r], nums[1..r], ..., nums[l - 1..r] are good subarrays, so add
// l to `ans`.
ans += l;
}
return ans;
}
};