Database 614. Second Degree Follower ¶ SQL 1 2 3 4 5 6 7 8SELECT Follower.follower, COUNT(DISTINCT Followee.follower) AS num FROM Follow AS Follower INNER JOIN Follow AS Followee ON (Follower.follower = Followee.followee) GROUP BY 1 ORDER BY 1; Was this page helpful? Thanks for your feedback! Thanks for your feedback! Help us improve this page by using our feedback form.