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760. Find Anagram Mappings

  • Time: $O(n)$
  • Space: $O(n)$
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class Solution {
 public:
  vector<int> anagramMappings(vector<int>& nums1, vector<int>& nums2) {
    vector<int> ans;
    unordered_map<int, stack<int>> numToIndices;

    for (int i = 0; i < nums2.size(); ++i)
      numToIndices[nums2[i]].push(i);

    for (const int num : nums1)
      ans.push_back(numToIndices[num].top()), numToIndices[num].pop();

    return ans;
  }
};

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class Solution {
  public int[] anagramMappings(int[] nums1, int[] nums2) {
    int[] ans = new int[nums1.length];
    Map<Integer, Deque<Integer>> numToIndices = new HashMap<>();

    for (int i = 0; i < nums2.length; ++i) {
      numToIndices.putIfAbsent(nums2[i], new ArrayDeque<>());
      numToIndices.get(nums2[i]).push(i);
    }

    for (int i = 0; i < nums1.length; ++i)
      ans[i] = numToIndices.get(nums1[i]).pop();

    return ans;
  }
}

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class Solution:
  def anagramMappings(self, nums1: list[int], nums2: list[int]) -> list[int]:
    numToIndices = collections.defaultdict(list)

    for i, num in enumerate(nums2):
      numToIndices[num].append(i)

    return [numToIndices[num].pop() for num in nums1]