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925. Long Pressed Name 👍

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class Solution {
 public:
  bool isLongPressedName(string name, string typed) {
    int i = 0;

    for (int j = 0; j < typed.length(); ++j)
      if (i < name.length() && name[i] == typed[j])
        ++i;
      else if (j == 0 || typed[j] != typed[j - 1])
        return false;

    return i == name.length();
  }
};

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class Solution {
  public boolean isLongPressedName(String name, String typed) {
    int i = 0;

    for (int j = 0; j < typed.length(); ++j)
      if (i < name.length() && name.charAt(i) == typed.charAt(j))
        ++i;
      else if (j == 0 || typed.charAt(j) != typed.charAt(j - 1))
        return false;

    return i == name.length();
  }
}

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class Solution:
  def isLongPressedName(self, name: str, typed: str) -> bool:
    i = 0

    for j, t in enumerate(typed):
      if i < len(name) and name[i] == t:
        i += 1
      elif j == 0 or t != typed[j - 1]:
        return False

    return i == len(name)